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输液直管道流-固耦合振动响应计算方法与应用

田瑞 常亮 韩涛 聂小华

田瑞, 常亮, 韩涛, 聂小华. 输液直管道流-固耦合振动响应计算方法与应用[J]. 应用数学和力学, 2024, 45(12): 1494-1505. doi: 10.21656/1000-0887.440291
引用本文: 田瑞, 常亮, 韩涛, 聂小华. 输液直管道流-固耦合振动响应计算方法与应用[J]. 应用数学和力学, 2024, 45(12): 1494-1505. doi: 10.21656/1000-0887.440291
TIAN Rui, CHANG Liang, HAN Tao, NIE Xiaohua. The Calculation Method and Application of Fluid-Solid Coupling Vibration Responses of Straight Infusion Pipeline[J]. Applied Mathematics and Mechanics, 2024, 45(12): 1494-1505. doi: 10.21656/1000-0887.440291
Citation: TIAN Rui, CHANG Liang, HAN Tao, NIE Xiaohua. The Calculation Method and Application of Fluid-Solid Coupling Vibration Responses of Straight Infusion Pipeline[J]. Applied Mathematics and Mechanics, 2024, 45(12): 1494-1505. doi: 10.21656/1000-0887.440291

输液直管道流-固耦合振动响应计算方法与应用

doi: 10.21656/1000-0887.440291
详细信息
    作者简介:

    田瑞(1993—),男,工程师,硕士(通讯作者. E-mail: 458519989@qq.com)

  • 中图分类号: V214

The Calculation Method and Application of Fluid-Solid Coupling Vibration Responses of Straight Infusion Pipeline

  • 摘要: 输液管道系统中存在液体压力脉动和管道结构的高度非线性耦合效应,在外激励作用下将产生剧烈的耦合振动现象,严重时会导致输液管道及连接结构失效.针对输液管道流-固耦合振动响应解析方法缺乏,研究了基于微分变换法(DTM)求解含复杂支承的输液管道系统动力学特性及振动响应理论,基于Bernoulli-Euler梁理论建立了跨中含复杂弹性支承的输液直管道流-固耦合振动微分方程,详细推导了基于DTM计算简支、含附加弹性支承输液直管道系统固有频率、位移响应及支承约束反力的表达式,研究了输液管道内压强、流速及附加支承刚度和位置对管道系统固有频率、支承约束反力的影响,并基于结构有限元分析方法验证了DTM的计算精度.研究表明:采用DTM计算含复杂支承输液管道系统流-固耦合振动特性及响应的精度高、适用性强,尤其在复杂边界以及跨中含有附加支承管道系统振动响应计算方面具有明显的优势,基于DTM可以便捷计算流固耦合管道系统强迫振动中的力学响应,为管道及其连接结构的设计提供理论依据.
  • 图  1  简支输液管道系统简化模型

    Figure  1.  The simplified model for the simple support infusion pipeline system

    图  2  附加单个弹性支承简支输液管道系统简化模型

    Figure  2.  A simple support infusion pipeline system model with an additional elastic support

    图  3  流速和压强对输液管道系统固有频率的影响

      为了解释图中的颜色,读者可以参考本文的电子网页版本,后同.

    Figure  3.  Effects of the flow rate and the pressure on natural frequencies of the infusion piping system

    图  4  不同外激励工况下流速和压强对约束反力的影响

    Figure  4.  Influences of the flow rate and the pressure on restrained reactions under different external excitation conditions

    表  1  DTM中基本数学运算[19]

    Table  1.   Basic mathematical operations in the DTM[19]

    original function conversion function
    w(x)=y(xz(x) W(k)=Y(kZ(k)
    w(x)=Ay(x) W(k)=AY(k)
    $w(x)=\frac{\mathrm{d} y(x)}{\mathrm{d} x} $ W(k)=(k+1)Y(k+1)
    $w(x)=\frac{\mathrm{d}^{n} y(x)}{\mathrm{d} x^{n}} $ W(k)=(k+1)(k+2)…(k+n)Y(k+n)
    w(x)=y(x)z(x) $ W(k)=\sum\limits_{l=0}^{k} Y(l) Z(k-l)$
    w(x)=xm $ W(k)=\delta(k-m)= \begin{cases}1, & k=m \\ 0, & k \neq m\end{cases}$
    下载: 导出CSV

    表  2  DTM中典型边界条件的转换[20]

    Table  2.   Typical boundary conditions and transition conditions in DTM[20]

    boundary type boundary condition conversion condition
    η(0)=η″(0)=0
    η(1)=η″(1)=0
    W(0)=W(2)=0
    $\sum\limits_{k=0}^{N} W(k)=\sum\limits_{k=0}^{N} k(k-1) W(k)=0 $
    η(0)=η′(0)=0
    η″(1)=η'''(1)=0
    W(0)=W(1)=0
    $ \sum\limits_{k=0}^{N} k(k-1) W(k)=\sum\limits_{k=0}^{N} k(k-1)(k-2) W(k)=0$
    η(0)=η′(0)=0
    η(1)=η″(1)==0
    W(0)=W(1)=0
    $\sum\limits_{k=0}^{N} W(k)=\sum\limits_{k=0}^{N} k(k-1) W(k)=0 $
    η(0)=η′(0)=0
    η(1)=η′(1)=0
    W(0)=W(1)=0
    $ \sum\limits_{k=0}^{N} W(k)=\sum\limits_{k=0}^{N} k W(k)=0$
    下载: 导出CSV

    表  3  简支输液管道系统固有频率计算结果

    Table  3.   Calculation results of natural frequencies of the simple support infusion pipeline system

    flow condition natural frequency fi/Hz error δ/%
    P/MPa Vf/(m/s) i FEM DTM
    0 0 1 86.772 86.772 0
    2 347.134 346.549 0.17
    20 10 1 69.0 69.0 0
    2 330.768 330.189 0.18
    30 20 1 57.80 57.80 0
    2 322.1 321.491 0.19
    下载: 导出CSV

    表  4  输液管道系统简支端约束反力

    Table  4.   Constraining reactions at the simple support end of the infusion pipeline system

    excitation frequency ωf flow condition constrained reaction force R1/N error δ/%
    P/MPa Vf/(m/s) FEM DTM
    0.5ω1 0 0 17.018 17.166 0.87
    20 10 30.914 31.109 0.63
    30 20 58.257 58.852 1
    ω1 0 0 2 526.348 2 527.190 0.03
    20 10 27.528 27.692 0.6
    30 20 17.129 17.343 0.5
    1.5ω1 0 0 6.339 6.242 1.5
    20 10 4.497 4.187 6.7
    30 20 3.808 3.518 7.6
    下载: 导出CSV

    表  5  等支承约束反力设计

    Table  5.   The equal support constrained reaction force design

    flow condition ωf optimal addition stiffness k/(kN/m) f1/Hz constrained reaction force Rj/N error δ/%
    P/MPa Vf/(m/s) j DTM FEM
    20 10 1 12.407 12.112 2.38
    0.5ω1 416.0 110.942 k 12.40 12.435 0.28
    2 12.407 12.112 2.38
    1 30.569 30.410 0.52
    ω1 347.1 105.260 k 30.540 30.813 0.89
    2 30.569 30.410 0.52
    1 9.224 9.396 1.86
    1.5ω1 231.8 94.920 k 9.215 9.181 0.37
    2 9.224 9.396 1.86
    30 20 1 14.293 14.0 2.05
    0.5ω1 402.3 103.137 k 14.279 14.330 0.36
    2 14.293 14.0 2.05
    1 55.774 55.925 0.27
    ω1 332.6 96.927 k 55.722 56.521 1.43
    2 55.774 55.925 0.27
    1 7.144 7.276 1.84
    1.5ω1 217.5 85.606 k 7.138 7.126 0.17
    2 7.144 7.276 1.84
    下载: 导出CSV
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出版历程
  • 收稿日期:  2023-09-26
  • 修回日期:  2024-02-22
  • 刊出日期:  2024-12-01

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